C++ left arrow operator

Posted on July 29, 2016

Sometimes you have a pointer to a class, and you want to invoke a method. You can use the -> operator for that.

So what do you do when you have a pointer to a method, and want to invoke it on a class? Use the <- operator!

#include <iostream>
template<class T>
struct larrow {
    larrow(T* a_) : a(a_) { }
    T* a;
template <class T, class R>
R operator<(R (T::* f)(), larrow<T> it) {
    return (it.a->*f)();
template<class T>
larrow<T> operator-(T& a) {
    return larrow<T>(&a);
struct C {
    void f() { std::cout << "foo\n"; }    
int main() {
    C x;